C Program To Safe Out Whether or now now not A Given String Is An Identifier Or Not

C program to get out whether a given string is an identifier or now now not.
A string is known as an identifier when he follows these tips:

  • The first letter ought to be alphabet(every capital or minute i.e. A-Z,a-z) or underscore(_).
  • After first letter it contains sequence of alphabet or digits(0-9) or underscore(_) but now now not like any particular image(#,@,$,%,^,& and loads others.) and condo( ).

Urged:  Java programming (newcomers)

#consist of
#consist of
#consist of
primary (){ //code by
char string [50];
printf (“Enter value to be identified: “);
scanf (“%s”, string);
int length = strlen (string) – 1;
bool alpha_string = false;
if ( string [0] >= ‘A’ && string [0] <= 'Z' )
alpha_string = true;
if ( string [0] >= ‘a’ && string [0] <= 'z' )
alpha_string = true;
bool underScore = true;
if ( string [length] == ‘_’ )
underScore = false;
int num = 0;
for ( int i = 1; i <= length; i++ ) {
if ( string [i] == ‘_’ )
num = 0;
if ( num == 2 ) {
underScore = false;
if ( alpha_string && underScore)
printf (“Reply: %s is a legitimate identifiern”, string);
printf (“Reply: %s is now now not a legitimate identifiern”, string);
} //code by Afolabi Achiever (techbytebox)

Urged: Complete E book on Guidelines on how to set up Xampp
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