C Program To Salvage Out Whether or now now not A Given String Is An Identifier Or Not

C program to search out out whether or now now not a given string is an identifier or now now not.
A string is known as an identifier when he follows these solutions:

• The first letter might well well honest quiet be alphabet(each capital or little i.e. A-Z,a-z) or underscore(_).
• After first letter it incorporates sequence of alphabet or digits(0-9) or underscore(_) but now now not occupy any special image(#,@,$,%,^,& etc.) and utter( ).

Quick:  Java programming (newbies)

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essential (){ //code by techbytebox.com
char string [50];
printf (“Enter worth to be acknowledged: “);
scanf (“%s”, string);
int measurement = strlen (string) – 1;
bool alpha_string = false;
if ( string [0] >= ‘A’ && string [0] <= 'Z' )
alpha_string = true;
if ( string [0] >= ‘a’ && string [0] <= 'z' )
alpha_string = correct;
bool underScore = correct;
if ( string [length] == ‘_’ )
underScore = false;
int num = 0;
for ( int i = 1; i <= measurement; i++ ) {
if ( string [i] == ‘_’ )
num++;
else
num = 0;
if ( num == 2 ) {
underScore = false;
shatter;
}}
if ( alpha_string && underScore)
printf (“Solution: %s is a sound identifiern”, string);
else
printf (“Solution: %s is now now not a sound identifiern”, string);
getche();
} //code by Afolabi Achiever (techbytebox)

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